2.5t^2=0/8t

Solution for 2.5t^2=0/8t equation:

2.5t^2=0/8t

We move all terms to the left:

2.5t^2-(0/8t)=0


Domain of the equation: 8t)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

2.5t^2-(+0/8t)=0

We get rid of parentheses

2.5t^2-0/8t=0

We multiply all the terms by the denominator


(2.5t^2)*8t-0=0

We add all the numbers together, and all the variables

(2.5t^2)*8t=0

We multiply parentheses

16t^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{32}=0$